Physics XII - Electric Potential 01

Question : 1

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n identical capacitors first connected in series and then in parallel turn by turn. Their equivalent capacitance are C_Sand C_Prespectively. The ratio of   is

Options:

	n
	n2

Solution :

(D)

C_P= nC

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Question : 2

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There are four identical equispaced parallel plates each of area A and placed d distance apart as shown. The equivalent capacitance between a and b is

                          1                A

              a

                           2                      d

                           3

                           4

              b

Options:

Solution :

(D)

Each gap is a capacitor. Redraw the circuit.

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Question : 3

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What is equivalent capacitance between points X and Y in the given network?

        

          

Options:

	2C
	4C

Solution :

(C)

Redraw the circuit after removing short circuited capacitors.

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Question : 4

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In the following circuit the equivalent capacitance between points P and Q in the given network [each capacitor is of capacitance C], is

               

Options:

Solution :

(A)

Given network can be redrawn as

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Question : 5

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Infinite number of capacitors each of capacitance C are connected as shown. The equivalent capacitance between points A and B is given by

          

Options:

Solution :

(B)

If one segment is removed total number of segments still remains infinity, that is equivalent capacitance upto XY is same as equivalent capacitance upto AB.

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Question : 6

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When capacitors are connected in parallel with source of emf, then

Options:

	Total potential of source is equally divided to all capacitors
	Potential across any one capacitor is same as emf of source
	Charge in each capacitor may be same
	Both (2) & (3)

Solution :

(D)

In parallel connection they have common terminals.

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Question : 7

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Four capacitors are connected across an emf source as shown in the circuit. The potential at point A is

         

Options:

	4 V
	3 V
	2 V
	1 V

Solution :

(C)

Q is charge in 3 μF capacitor then

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Question : 8

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What is charge drawn from the battery by combination of capacitors as shown in the figure?

             

Options:

	6 μC
	12 μC
	15 μC
	18 μC

Solution :

(D)

Equivalent capacitance of network

C_EQ= (2 + 3 + 1) μF

         = 6 μF

q = C_EQ× V

   = 6 × 3 μC = 18 μC

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Question : 9

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The equivalent capacitance between point A and B in the given network is

         

Options:

Solution :

(C)

From symmetry it can be redrawn as

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Question : 10

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Each capacitor is of same capacitance C as shown in the network. Find equivalent capacitance between points A and B.

                 

Options:

Solution :

(B)

Due to symmetry potential at V_P= V_Qand potential at V_X= V_Y, it can be redrawn as