Tuesday, March 28, 2017

Chemistry XII -Chemical Kinetics 03

Question : 1
(skipped)
The correct expression for a reaction of 1st order kinetics is [where [A0] = initial concentration, [A] = final concentration]
Options:

[A] = [A0]e–kt

ln[A] = kt + ln[A0]

Both (1) & (3)
Solution :
(2)
Correct expression
[A] = [A0]e–kt
for 1st order reaction in exponential form
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Question : 2
(skipped)
For a second order reaction, the correct graph shown is
Options:



Solution :
(3)
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Question : 3
(skipped)
For a zero order reaction, if the initial concentration is tripled, the half life period becomes
Options:


3 times

Remains unaffected
Solution :
(3)
For zero order reaction t1/2 ∝ [A0 ]
Hence half life becomes 3 times
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Question : 4
(skipped)
Find rate constant for a first order reaction if t99.9% is 1000 minutes
Options:

100 min–1
6.93 × 10–3 min–1

6.93 × 10–4 min–1

1000 min–1
Solution :
(2)
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Question : 5
(skipped)
The graph shown below i.e. represents

Options:

Zero order reaction

1st order reaction

2nd order reaction
3rd order reaction
Solution :
(4)
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Question : 6
(skipped)
If for a reaction of radioactive decay 20% of the reaction is completed in 50 minutes, then in how much time 60% of the reaction is completed [log 2 = 0.30, log 3 = 0.477, log 6 = 0.778, log 8 = 0.90]
Options:

25 min

100 min

150 min
200 min
Solution :
(4)
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Question : 7
(skipped)
Slope of the graph between ln[A] vs time for 1st order reaction is [where [A] = final concentration]
Options:

k
–k

–ln[A0]

Solution :
(2)
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Question : 8
(skipped)
Starting with 100 g of radioactive substance, how much of it is left after two half life?
Options:

100 g

50 g
25 g

Substance gets fully reacted
Solution :
(3)
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Question : 9
(skipped)
For a first order reaction the correct graph shown between log   versus time
Options:



Solution :
(3)
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Question : 10
(skipped)
For a zero order reaction, if 10% of the reactant is consumed in 10 minute, find half life period of reaction
Options:

0.693 min
50 min

100 min

693 min
Solution :
(2)
Zero order reaction

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