Tuesday, March 28, 2017

Chemistry XII - ElectroChemistry 06

Question : 1
(skipped)
In order to get higher value of  Ecell , the correct statement is
Options:
Concentration of cathode solution >> Concentration of anode solution

Concentration of anode solution >> Concentration of cathode solution

Concentration of anode solution = Concentration of cathode solution

Ecell does not depend on concentration
Solution :
(1)
Ecell = (ERP)cathode – (ERP)anode
ERP ∝ [Mn+]
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Question : 2
(skipped)
Zn(s) + Cu+2(C1) → Zn+2(C2) + Cu(s); Ecell = x volt
2Zn(s) + 2Cu+2(C1) → 2Zn+2(C2) + 2Cu(s); Ecell = y volt
then the correct relation is
Options:

x = y2

y = x2

x = 2y
x = y
Solution :
(4)
Ecell is characteristic of the given redox
reaction and does not change with
multiplication factor.
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Question : 3
(skipped)
The electrode potential of hydrogen electrode at pOH = 10 is
Options:

+0.236 V
–0.236 V

+0.118 V

–0.118 V
Solution :
(2)
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Question : 4
(skipped)
At equilibrium Nernst’s equation becomes
Options:



Solution :
(1)
At equilibrium,
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Question : 5
(skipped)
Which of the following statement is incorrect?
Options:

Metals which have low S.R.P. value are strong reducing agent
Metals which have S.R.P. > 0 will be weakly electronegative

Metals which have low S.R.P. value, their oxides are thermally stable

Lithium has lowest value of S.R.P.
Solution :
(2)
The correct statements are facts.
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Question : 6
(skipped)
Ecell depends on
Options:

Volume of electrolyte solution taken

Size of electrode taken
Concentration of electrolyte solution taken

All of these
Solution :
(3)
Fact.
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Question : 7
(skipped)
Which of the following electrode represents metalmetal insoluble salt-anion electrode?
Options:

Zn(s)|Zn+2(aq)

Pt|Fe+2(aq), Fe+3(aq)

Pt, H2(g)|H+(aq)
Ag|AgCl|Cl(aq)
Solution :
(4)
The half cell representation suggests this.
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Question : 8
(skipped)
If a graph is plotted between EOX versus log[M+n], then the intercept and slope respectively are
Options:



Solution :
(1)
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Question : 9
(skipped)
The magnitude of potential of an electrode depends on
Options:

Nature of electrode

Concentration of ions

Temperature
All of these
Solution :
(4)
Fact.
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Question : 10
(skipped)
 If E°A+3/A  is y2 and 2  E°A/A+2 is y1, then E°A+3/A+2 will be
Options:

(y2 + y1)

y2 – y1

y1 – y2
3y2 + 2y1
Solution :
(4)

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