Question : 1
In concentration cell
Options:
Ecell = 0
| |
E°cell = 0 | |
ΔG° = 0 | |
All of these |
Solution :
(2)
In concentration cell both the half cell are
identical.
identical.
You scored 0 of 1
Question : 2
(skipped)
In the given concentration cell,
Pt(s)|H2(P2 atm)|H+(C2)||H+(C1)|H2(P1 atm)|Pt(s)
the cell reaction is spontaneous in forward direction if
Pt(s)|H2(P2 atm)|H+(C2)||H+(C1)|H2(P1 atm)|Pt(s)
the cell reaction is spontaneous in forward direction if
Options:
(C2)2P1 < (C1)2P2
| |
(C2)2P1 > (C2)2P2
| |
(C2)2P1 = (C1)2P2
| |
C1 + C2 = P1 + P2
|
Solution :
(1)
You scored 0 of 1
Question : 3
(skipped)
When equilibrium is attained in electrochemical cell, then
Options:
Electrode potential of anode > Electrode potential of cathode | |
Electrode potential of anode < Electrode potential of cathode | |
Electrode potential of anode = Electrode potential of cathode | |
Flow of electron is increased |
Solution :
(3)
At equilibrium, Ecell = 0
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Question : 4
(skipped)
In concentration cell
Options:
Anode is that electrode in which concentration of electrolyte solution is high | |
Cathode is that electrode in which concentration of electrolyte solution is low | |
Cathode is that electrode in which concentration of electrolyte solution is high | |
Any electrode can be made anode or cathode because both electrodes are of same material |
Solution :
(3)
Reduction potential of M|Mn+ is directly
proportional to [Mn+]
proportional to [Mn+]
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Question : 5
(skipped)
ΔG° may be equal to zero when the equilibrium constant (K) is
Options:
K > 1 | |
K < 1 | |
K = 1 | |
All of these |
Solution :
(3)
ΔG = ΔG° + RT ln Q
At equilibrium, ΔG = 0
∴ ΔG° = –RT ln K
= 0 if K = 1
At equilibrium, ΔG = 0
∴ ΔG° = –RT ln K
= 0 if K = 1
You scored 0 of 1
Question : 6
(skipped)
The emf of the cell
A|A+3(10–3 M)||A+3(10–1 M)|A is
A|A+3(10–3 M)||A+3(10–1 M)|A is
Options:
0.039 volt | |
0.089 volt | |
–0.059 volt | |
+0.059 volt |
Solution :
(1)
You scored 0 of 1
Question : 7
(skipped)
The reduction potential of the electrode is,
Pt|Cl2(10 atm)|2Cl–(10–5 M).
Pt|Cl2(10 atm)|2Cl–(10–5 M).
If E° Cl2/Cl– = 1.36 V
Options:
1.68 volt | |
–1.68 volt | |
1.18 volt | |
–1.18 volt |
Solution :
(1)
You scored 0 of 1
Question : 8
(skipped)
The correct relation is
Options:
Welectrical = –ΔG
| |
At equilibrium ΔG° = 0
| |
ΔG° = –2.303 nRT lnK
| |
Welectrical = F × Ecell
|
Solution :
(1)
Useful work done = ΔG = –nFEcell
You scored 0 of 1
Question : 9
(skipped)
For a particular electrochemical cell, which one of the following statements is correct?
Options:
Current flows from cathode to anode
| |
Ecell is constant having different concentration of ions
| |
Both E°cell and Ecell are constant having different concentrations of ions
| |
Neither E°cell nor Ecell is constant having different concentration of ions
|
Solution :
(1)
Fact
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Question : 10
(skipped)
The maximum work done for the following cell is,
A|A+3||B+2|B; E°cell = 0.30 volt
A|A+3||B+2|B; E°cell = 0.30 volt
Options:
280.65 kJ | |
305.60 kJ | |
109.16 kJ | |
173.7 kJ |
Solution :
(4)
ΔG° = o
−nFEcell
= –6 × 96500 × 0.30
= –173.7 kJ
−nFEcell
= –6 × 96500 × 0.30
= –173.7 kJ
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